MySQL PHP API :: 5 Original MySQL API (Mysql) :: 5.5 MySQL Functions :: 5.5.21 mysql_field_name

Section Navigation [Toggle]

5.5.21 `mysql_field_name`

mysql_field_name
Get the name of the specified field in a result

Warning

This extension is deprecated as of PHP 5.5.0, and will be removed in the future. Instead, the MySQLi or PDO_MySQL extension should be used. See also MySQL: choosing an API guide and related FAQ for more information. Alternatives to this function include:

mysqli_fetch_field_direct [name] or [orgname]

PDOStatement::getColumnMeta [name]

Description

string mysql_field_name(resource result,
                        int field_offset);

mysql_field_name returns the name of the specified field index.

Parameters

result: The result resource that is being evaluated. This result comes from a call to mysql_query.
field_offset: The numerical field offset. The field_offset starts at 0. If field_offset does not exist, an error of level E_WARNING is also issued.

Return Values

The name of the specified field index on success or FALSE on failure.

Examples

Example 5.29 mysql_field_name example


<?php
/* The users table consists of three fields:
 *   user_id
 *   username
 *   password.
 */
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
    die('Could not connect to MySQL server: ' . mysql_error());
}
$dbname = 'mydb';
$db_selected = mysql_select_db($dbname, $link);
if (!$db_selected) {
    die("Could not set $dbname: " . mysql_error());
}
$res = mysql_query('select * from users', $link);

echo mysql_field_name($res, 0) . "\n";
echo mysql_field_name($res, 2);
?>

The above example will output: